I would like to know how the complete url passed as a data in xml with
tag staffPhoto ,which can be used in <fo:external-graphic src=.....> ?
I tried to read the xml line which is generated via a program in this way,
<staffPhoto> url('file:C:///staff/beena.jpg') </staffPhoto>
In my xsl i wrote the below line to read the above xml line
<fo:external-graphic src="staffPhoto"/>
What is wrong in this ? I got the error message, Error with image URL
:staffPhoto (the system cannot find the file specified) and no base
URL is specified.
But if i copy paste the url path , the image will be loaded without any problem.
Please help me to solve this problem and is very crucial in my project.
I also tried the way you suggested to use the xsl:param ...
I am using
xml version 1.0 encoding "ISO-8859-1".
xsl:stylesheet version 1.0
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:fo="http://www.w3.org/1999/XSL/Format"
Thanks a lot.
Beena
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