depending on the postion() of a certain node I would like to select
another node with the same position.
It works if I invent a variable.
But I wonder if there is a way to do it without the use of a variable?
Not if you're using a predicate, because position() inside a predicate is
different from position() outside the predicate.
As DC said, it's much better to make your variable hold the position as a
number rather than as a text node in a result tree fragment: that is, to use
the select attribute.
In fact there's an XSLT 2.0 solution that doesn't require a predicate and
therefore doesn't require a variable:
<xsl:value-of select="../../subsequence(colspec, position(), 1)/@colname"/>
Michael Kay
http://www.saxonica.com/
XML:
<table>
<colspec colname="c1"/>
<colspec colname="c2"/>
<colspec colname="c3"/>
<row>
<entry colname="c1">r1_1</entry>
<entry colname="c2">r1_2</entry>
<entry colname="c3">r1_2</entry>
</row>
</table>
XSL:
<xsl:template match="entry">
<xsl:variable name="mypos">
<xsl:value-of select="position()"/>
</xsl:variable>
<xsl:value-of select="../../colspec[position() = $mypos]/@colname"/>
</xsl:template>
Best regards and thanks for your comments,
Norbert Heidbrink
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