As well as the answer to your question (A[...]/B/@v) you might like to note
that you don't have to use xsl:element and xsl:attribute. You can write the
much more concise
<Point PointAttribute="{A[(_at_)id='123']/B/@v}"/>
XSLT has a reputation for verbosity, but it doesn't have to be as bad as
people sometimes make it.
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: dalloro(_at_)gmail(_dot_)com [mailto:dalloro(_at_)gmail(_dot_)com]
Sent: 01 April 2005 08:22
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] (newby) define an attribute based on an attribute value
Hi,
I'm a newby in XSL tranformations. I need to trasform an XML file into
another XML file with a different structure.
Inside a template I build an element named Point that has several
attributes. The value of one of these attributes depends on the value
of an attribute in the source XML (the attribute v of the element B
that I filtered through the parent 'id', in the code below)
[snip]
<xsl:element name="Point">
[snip]
<xsl:attribute name="PointAttribute">
<xsl:value-of select="A[(_at_)id='123']/B[(_at_)v]"/>
</xsl:attribute>
[snip]
</xsl:element>
[snip]
I would like to obtain a 'Point' element with an attribute called
'PointAttribute' with the same value of the 'v' attribute of the
element 'B'.
What is the best way to deal with this problem?
I thank you for the help.
Best regards.
Livio.
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