My mistake - now I see. You're right, I wasn't declaring the xsl: namespace
prefix in "replace_string.xsl".
Here is what I have now in "replace_string.xsl":
<?xml version="1.0" encoding="UTF-8" ?>
<stylesheet
version="1.0"
xmlns="http://www.w3.org/1999/XSL/Transform"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
I just put in the last "xmlns:xsl" line. But it still doesn't work - I'm still
getting a blank page.
Here is the top of my main style sheet:
*---------------------------------
<?xml version='1.0'?>
<xsl:stylesheet
version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:msxsl="urn:schemas-microsoft-com:xslt">
<xsl:include href="replace_string.xsl" />
*---------------------------------
Is there something more I need to do?
mike(_at_)saxonica(_dot_)com 5/31/2005 12:42 PM >>>
We're using MSXML4 and I'm trying to get xsl:include to work
but I'm having trouble. I created file "replace_string.xsl"
that contains this:
<?xml version="1.0" encoding="UTF-8" ?>
<stylesheet version="1.0"
xmlns="http://www.w3.org/1999/XSL/Transform">
<xsl:template name="replace-string">
You haven't declared the xsl: namespace prefix.
(MSXML's error reporting is not always brilliant...)
Michael Kay
http://www.saxonica.com/
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