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RE: xsl:include problems

2005-05-31 10:00:12
My mistake - now I see.  You're right, I wasn't declaring the xsl: namespace 
prefix in "replace_string.xsl".

Here is what I have now in "replace_string.xsl":

<?xml version="1.0" encoding="UTF-8" ?>
<stylesheet
        version="1.0"
        xmlns="http://www.w3.org/1999/XSL/Transform";
        xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>

I just put in the last "xmlns:xsl" line.  But it still doesn't work - I'm still 
getting a blank page.

Here is the top of my main style sheet:
*---------------------------------
<?xml version='1.0'?>
<xsl:stylesheet
        version="1.0"
        xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
        xmlns:msxsl="urn:schemas-microsoft-com:xslt">

<xsl:include href="replace_string.xsl" />
*---------------------------------

Is there something more I need to do?

mike(_at_)saxonica(_dot_)com 5/31/2005 12:42 PM >>>
We're using MSXML4 and I'm trying to get xsl:include to work 
but I'm having trouble.  I created file "replace_string.xsl" 
that contains this:

<?xml version="1.0" encoding="UTF-8" ?>
<stylesheet version="1.0" 
xmlns="http://www.w3.org/1999/XSL/Transform";>

<xsl:template name="replace-string">


You haven't declared the xsl: namespace prefix.

(MSXML's error reporting is not always brilliant...)

Michael Kay
http://www.saxonica.com/ 



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