You've got some pretty deep misunderstanding of what goes in the "match"
attribute, because two of us have tried to explain your mistake and somehow
you haven't grasped it.
You might find this little tutorial on patterns helpful:
http://www.saxonica.com/documentation/patterns/intro.html
Note also that xsl:apply-templates does not have a match attribute, it only
has a select attribute.
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: Jessica Spiteri [mailto:gryzlaw(_at_)hotmail(_dot_)com]
Sent: 31 May 2005 07:52
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: RE: [xsl] template name in attributes
so if i also have:
<xsl:template match="login">
...
</xsl:template>
<xsl:template match="t_news">
...
</xsl:template>
<xsl:template match="t_threads">
...
</xsl:template>
it has to be changed to:
<xsl:template match="left">
<xsl:for-each select="box">
<xsl:apply-templates match="@name"/>
</xsl:for-each>
</xsl:template>
for it to automatically detect from the attribut value which
template to
process?
Date: Mon, 30 May 2005 22:34:19 +0000
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
From: "Aron Bock" <aronbock(_at_)hotmail(_dot_)com>
Subject: RE: [xsl] template name in attributes
Message-ID: <BAY107-F924574AE1D8761ECAFB21D8030(_at_)phx(_dot_)gbl>
i have the xml:
<left>
<box name="login"/>
<box name="quicksearch"/>
<box name="t_news"/>
<box name="t_threads"/>
</left>
and the xsl:
<xsl:template match="left">
<xsl:for-each select="box">
<xsl:apply-templates select="@name"/>
</xsl:for-each>
</xsl:template>
This much is kosher.
<xsl:template match="quicksearch">
...
</xsl:template>
This, however, doesn't work as expected because the value of
the match
attribute should [usually] be the name of the matched
element or attribute,
not their values. Thus, it would something like:
match="@name"
or
match="@name[. = 'quicksearch']"
The "usually" above is because it's possible to match using non
name-specific expressions: node() to match any node, text()
for text nodes,
@* for attributes, etc.
why is the output only the value of the attribute not the
template that
matches the value of the attribute?
So now we know why the template doesn't fire. The "value of
the attribute"
is being output because XSLT has default, behind-the-scenes
templates that
automatically output certain nodes, if not overridden.
Thus, if you left
things as they were, then add the following template, you
wouldn't get even
the attribute value output:
<xsl:template match="@*"/>
Regards,
--A
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