Zak,
You'll want to use the xpath document() function--it allows you to refer to
additional, external XML file(s). You should be able to find several
examples of usage on the Net.
Regards,
--A
From: "dti mail" <zaknixon(_at_)davidson-tech(_dot_)com>
Reply-To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
To: <xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com>
Subject: [xsl] XML / XSLT Transformations with multiple files &
transformations.
Date: Tue, 24 May 2005 09:46:08 -0500
Hello all. I need some help with XSLT and understanding how I can
solve my problem. I have a set of 4 files, which are sampled below:
-- Job.xml--
<job id = "12"/>
<job id = "22"/>
<job id = "32"/>
-- Task.xml --
<task id ="1">
<job ref = "12"/>
</task>
<task id ="2">
<job ref = "22"/>
</task>
<task id ="3">
<job ref = "32"/>
</task>
-- MyTasks.xml --
<mytask id = "1">
<task-ref id="2"/>
<task-ref id="3"/>
</mytask>
<mytask id = "2">
<task-ref id="2"/>
<task-ref id="3"/>
</mytask>
-- Configuration.xml --
<conf>
<mytask-ref id = "1"/>
<mytask-ref id = "2"/>
</conf>
The ref tags indicate the ids of the elements to use in the appropriate
files.
Here is what I wish my output to look like:
<conf>
<mytask id = "1">
<task id ="2">
<job id = "22"/>
</task>
<task id ="3">
<job id= "32"/>
</task>
</mytask>
<mytask id = "2">
<task id ="2">
<job id = "22"/>
</task>
<task id ="3">
<job id= "32"/>
</task>
</mytask>
</conf>
============ END OUT =================
Can anyone give me any pointers on how to acheive this ?
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