Aron Bock wrote:
Rahil,
I (for one) am unclear on the hierarchy with which you're working--do
you have SubConcept as a "parent" of sibling SubConcept? That seems
to be the case with
<SubConcept name="Broken..."/> and
<SubConcept name="Level1"/>
Both of these are sibling nodes. However the child of <SubConcept
name="Level1"/> has a reference to <SubConcept name="Broken..."/> via
the 'ref' value.
Also, wwhile you refer to "Time", I assume you mean "NextTime"?
Yeah it really means 'NextTime'. Had originally intended to ask two
queries, for which Id written 'Time', but then decided not to complicate
the mail !.
Hope I clarified your doubt. Else please let me know.
Thanks
Rahil
From: Rahil <qamar_rahil(_at_)yahoo(_dot_)co(_dot_)uk>
Reply-To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] backtracking to find all parents till root[again]
Date: Tue, 24 May 2005 11:52:05 +0100
How do I backtrack to the root element from the result-generating
node? Hence if my given structure is of the form:
<Top>
<SubConcepts>
<SubConcept id="990" name="Level1">
<Child ref="567">Child1</Child>
<Value ref="456">hasFeature BrokenBolt</Value>
</SubConcept>
<SubConcept id="456" name="BrokenBolt">
<Child ref="345">Child2</Child>
<Value ref="123">hasProperty NextTime</Value>
</SubConcept>
</SubConcepts>
</Top>
I find my result in the <Value ref="123"> node with the contained
value 'Time'. I can find the parent of this with the @name
Match found: Next
Parent: BrokenBolt
Parent: Level1
Parent: SubConcepts
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