Please try this XSL ..
(there seems to be well formdness error in the XML you
posted)
<?xml version="1.0"?>
<xsl:stylesheet
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="1.0">
<xsl:output method="xml" encoding="UTF-8" indent="yes"
/>
<xsl:template match="/BigList">
<select id="SmallElements">
<xsl:for-each select=".//Name">
<xsl:sort select="." />
<option
value="{preceding-sibling::Code[1]}"><xsl:value-of
select="." /></option>
</xsl:for-each>
</select>
</xsl:template>
</xsl:stylesheet>
Regards,
Mukul
--- knocte <knocte(_at_)gmail(_dot_)com> wrote:
Hello list!
I have a problem of sorting when forming a SELECT
INPUT BOX.
The XML:
<BigList>
<BigElement>
<Code>XXP</Code>
<SmallList>
<SmallElement>
<Code>001</Code1>
<Name>A</Name>
</SmallElement>
<SmallElement>
<Code>002</Code1>
<Name>X</Name>
</SmallElement>
</SmallList>
</BigElement>
<BigElement>
<Code>YYJ</Code>
<SmallList>
<SmallElement>
<Code>01</Code1>
<Name>B</Name>
</SmallElement>
<SmallElement>
<Code>02</Code1>
<Name>Z</Name>
</SmallElement>
</SmallList>
</Element>
</BigList>
The XSLT:
<select id="SmallElements">
<xsl:for-each select="BigList/BigElement">
<xsl:for-each select="SmallList/SmallElement">
<option value="Code">
<xsl:value-of select="Name" />
</option>
</xsl:for-each>
</xsl:for-each>
</select>
Results:
<select id="SmallElements">
<option value="001">A</option>
<option value="002">X</option>
<option value="01">B</option>
<option value="02">Z</option>
</select>
How can I sort by the name? I mean, my expected
results are:
<select id="SmallElements">
<option value="001">A</option>
<option value="01">B</option>
<option value="002">X</option>
<option value="02">Z</option>
</select>
Thanks in advance!
Andrew
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