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Re: How can I sort this?

2005-05-24 01:24:44
Please try this XSL ..
(there seems to be well formdness error in the XML you
posted)

<?xml version="1.0"?> 
<xsl:stylesheet
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
version="1.0">
 
<xsl:output method="xml" encoding="UTF-8" indent="yes"
/> 

<xsl:template match="/BigList">
   <select id="SmallElements">
    <xsl:for-each select=".//Name">
      <xsl:sort select="." />
      <option
value="{preceding-sibling::Code[1]}"><xsl:value-of
select="." /></option>         
    </xsl:for-each>
   </select> 
</xsl:template>

</xsl:stylesheet>

Regards,
Mukul

--- knocte <knocte(_at_)gmail(_dot_)com> wrote:
Hello list!

I have a problem of sorting when forming a SELECT
INPUT BOX.


The XML:

<BigList>
  <BigElement>
    <Code>XXP</Code>
    <SmallList>
      <SmallElement>
        <Code>001</Code1>
        <Name>A</Name>
      </SmallElement>
      <SmallElement>
        <Code>002</Code1>
        <Name>X</Name>
      </SmallElement>
    </SmallList>
  </BigElement>
  <BigElement>
    <Code>YYJ</Code>
    <SmallList>
      <SmallElement>
        <Code>01</Code1>
        <Name>B</Name>
      </SmallElement>
      <SmallElement>
        <Code>02</Code1>
        <Name>Z</Name>
      </SmallElement>
    </SmallList>
  </Element>
</BigList>


The XSLT:

<select id="SmallElements">
  <xsl:for-each select="BigList/BigElement">
    <xsl:for-each select="SmallList/SmallElement">
      <option value="Code">
        <xsl:value-of select="Name" />
      </option>
    </xsl:for-each>
  </xsl:for-each>
</select>

Results:

<select id="SmallElements">
  <option value="001">A</option>
  <option value="002">X</option>
  <option value="01">B</option>
  <option value="02">Z</option>
</select>


How can I sort by the name? I mean, my expected
results are:

<select id="SmallElements">
  <option value="001">A</option>
  <option value="01">B</option>
  <option value="002">X</option>
  <option value="02">Z</option>
</select>


Thanks in advance!

  Andrew


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