Another solution to add to the list you've been given: In XSLT 2.0 you can
do
<td bgcolor="{if (position() mod 2) then 'black' else 'white'}">
...
</td>
If you want to be terse and don't mind being obscure, you can write things
in XSLT 1.0 like
<td bgcolor="#{substring('FFFFFF000000', (position() mod 2 * 6) + 1, 6)}">
...
</td>
Michael Kay
-----Original Message-----
From: Rolando Isidoro [mailto:rli(_at_)uninova(_dot_)pt]
Sent: 20 May 2005 19:34
To: XSL Mulberrytech
Subject: [xsl] xsl:variable with hex color values
Hi, I'm trying implementing a XSL which distinguishes odd and
even row
of a table by using different colors. My solution involves
the testing
of the number or the position, something like this:
<xsl:choose>
<xsl:when test="position() mod 2">
<td bgcolor = "...">
....
</td>
</xsl:when>
<xsl:otherwise>
<td bgcolor = "...">
....
</td>
</xsl:otherwise>
</xsl:choose>
the existing code inside each of the <td>'s differs only in the
background color, which resolves into big time redundancy. Is
there any
way to assign the color value to a variable and then using it in the
bgcolor attribute? I've tried using something like <xsl:variable
name="bg" select="Black"> and then <td bgcolor = "$bg"> but
it doesn't
seem to work. I've tried with hex color values, which is my
objective,
and it didn't work either.
Thanks, Rolando
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