"Dimitre" == Dimitre Novatchev <dnovatchev(_at_)gmail(_dot_)com> writes:
Dimitre> Or be prepared for all kinds of a nasty surprise
Dimitre> following the fact that the value of
>>
Dimitre> my:f($x) is my:f($x)
>>
Dimitre> is generally not guaranteed to be true()
>> It isn't, as if either function returns an atomic sequence,
>> you get a type error.
Dimitre> Sure, I must have added that my:f() is of type node()*.
Not really. My comment was off the ball.
Since $x may raise an error anyway.
To be pedantic, my:f($x) is my:f($x) should always evaluate to true()
in the absence of errors. But that can be taken as read.
--
Colin Adams
Preston Lancashire
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