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RE: displaying unique entries in a list

2005-05-09 02:40:21
Hi Mukul,

Thanks again for providing a fix to my problem.

Many thanks,

Mike

-----Original Message-----
From: Mukul Gandhi [mailto:mukul_gandhi(_at_)yahoo(_dot_)com]
Sent: 09 May 2005 10:30
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] displaying unique entries in a list


I modified the stylesheet as follows.. Its working.

<?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>

<xsl:output method="html" />

<xsl:template match="/xml">
  <html>
    <body>
      <h2>Test example of List output</h2>
      <hr/>
      <!--########## Begin Main Document ##########-->
      <xsl:apply-templates select="List" />
    </body>
  </html>
</xsl:template>

<!--######## Template for Department Main table data
######-->
<xsl:template match="List">
  <table border="1" width="100%">
    <xsl:apply-templates select="Entry/Department"/>
  </table>
</xsl:template>

<!--### Displays first page departments only ###-->
<xsl:template match="Entry/Department">
  <xsl:if test="not(. = preceding::Department)">
    <tr>
      <td>
       <span style="color:#000000">
         <a href=""><xsl:value-of select="." /></a>
       </span>
      </td>
    </tr>
  </xsl:if>
</xsl:template>

</xsl:stylesheet>

Regards,
Mukul

--- "Hallas,M" <M(_dot_)Hallas(_at_)lse(_dot_)ac(_dot_)uk> wrote:
Dear all,

Hope that you can help with this problem I have
displaying a list of data.

My XML looks like this:

<xml>
<List>
      <Entry>
              <Session>2004/5</Session>
              <Department>Accounting and Finance</Department>
      </Entry>
      <Entry>
              <Session>2004/5</Session>
              <Department>Accounting and Finance</Department>
      </Entry>
      <Entry>
              <Session>2004/5</Session>
              <Department>Maths</Department>
      </Entry>
      <Entry>
              <Session>2004/5</Session>
              <Department>Maths</Department>
      </Entry>
      <Entry>
              <Session>2004/5</Session>
              <Department>Economic History</Department>
      </Entry>
</List>
</xml>

My xslt example is below:

<?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:template match="/">
<html>
      <body>
              <h2>Test example of List output</h2>
              <hr/>
               <!--########## Begin Main Document ##########-->
               <xsl:apply-templates />
      </body>
</html>
</xsl:template>

<!--######## Template for Department Main table data
######-->
<xsl:template match="List">
      <table border="1" width="100%">
              <xsl:apply-templates select="Department"/>
      </table>
</xsl:template>

<!--### Displays first page departments only ###-->
<xsl:template match="Department">
  <xsl:for-each select="/List/Entry/Department[not(.
= preceding::Department)]">
            <tr>
              <td>
                 <span style="color:#000000">
                      <a href=""><xsl:value-of select="." /></a>
                 </span>
             </td>
            </tr>
  </xsl:for-each>
</xsl:template>
</xsl:stylesheet>

An earlier posted fix in the xlst allowed me to
display just single unique entries in the html like
this:

      Accounting and Finance
      Maths
      Economic History

However I now get multiples of these unique values
rather than one single list of the unique values.

Am I calling the template root incorrectly in the
xslt? 
Should I be using a loop of some sort to display the
unique values only once?

Many thanks,


Mike








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