<xsl:number/> with no attributes will give you what you want.
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: c p [mailto:bugs75il(_at_)yahoo(_dot_)com]
Sent: 05 May 2005 18:07
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Node position and numbering.
Hello all,
I have following XML:
-----------------------------------------
<?xml version="1.0" encoding="UTF-8"?>
<service>
<title>Printing the Page</title>
<somenode>node content might go here.</somenode>
<step>Go to File menu</step>
<step>Select Print</step>
<step>Click Print</step>
<somenode>you are all done.</somenode>
</service>
-----------------------------------------
As you can see the XML has a <service> node with a
whole bunch of other child nodes. Out of all the
child nodes, I am interested in getting the position
for <step> nodes only. Its pretty simple but there's
a twist. In the example above if I did
<xsl:apply-templates match="service"/> and then for
each child node I did a position() then it would give
me numbers 2,4,and 5 for the <step> nodes. However
thats not what I want. I want it to give me numbers
1,2,3 for the <step> nodes. The way I can get that is
by doing <xsl:apply-templates match="service/step"/>,
unfortunately due to the complexity of my XSL and XML
structure I cannot do that. Is there a way to achieve
this so I can get an output that will look like this:
---------------------------------------------
1. Go to File menu
2. Select Print
3. Click Print
---------------------------------------------
Note: Its not always guaranteed that the first <step>
node will start after <title> node or any other node.
It could be random.
Any help would be appreciated.
Thx,
C
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