XML document
<?xml version="1.0"?>
<Unit xmlns="http://www.xml.com/xml/unit";
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance";
xsi:schemaLocation="http://www.xml.com/xml/unit unit.xsd">
<Units>
<Unit_Code>5555</Unit_Code>
<Unit_Name>System</Unit_Name>
</Units>
</Unit>
XSL Stylesheet
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
xmlns:unit="http://www.monash.edu.au/xml/unitManagement"; >
<xsl:output method="xml"/>
<xsl:template match="/">
<xsl:element name="Unit_Planning" xmlns="http://www.xml.com/xml/unit";
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance";
xsi:schemaLocation="http://www.xml.com/xml/unit newUnit.xsd">
<xsl:for-each select="unit:Unit/unit:Units">
<xsl:element name="Unit">
<xsl:element name="Unit_Code">
<xsl:value-of select="unit:Unit_Code"/>
</xsl:element>
<xsl:element name="Unit_Name">
<xsl:value-of select="unit:Unit_Name"/>
</xsl:element>
</xsl:element>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
I wish to display XML that will validate to a new XML schema file.
Hope to display XML
<?xml version="1.0"?>
<Unit xmlns="http://www.xml.com/xml/unit";
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance";
xsi:schemaLocation="http://www.xml.com/xml/unit newUnit.xsd">
<Units>
<Unit_Code>5555</Unit_Code>
<Unit_Name>System</Unit_Name>
</Units>
</Unit>
Can anyone out there pls help me out? I fail to display the exactly what I
want. I need to validate to a new schema from what I create. It still be
generate the XML file but do not include any of the schemalocation details
in the root element.
Can anyone show me how to do it in XSL? I wish to know a way to validate to
a new schema and show all the details.
Thanks
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