Hi Mat,
You may try something like this .. (Hope I got the
requirements right)
<?xml version="1.0"?>
<xsl:stylesheet
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
xmlns:common="http://exslt.org/common";
version="1.0">
<xsl:output method="text" />
<xsl:param name="siteID" select="'1'" />
<xsl:template match="/">
<xsl:variable name="rtf">
<xsl:for-each select="//exsites">
<xsl:choose>
<xsl:when test=". = $siteID">
<menu name="{parent::menu/@name}">
<process x="yes" />
</menu>
</xsl:when>
<xsl:otherwise>
<menu name="{parent::menu/@name}">
<process x="no" />
</menu>
</xsl:otherwise>
</xsl:choose>
</xsl:for-each>
</xsl:variable>
<xsl:for-each
select="common:node-set($rtf)/menu/process[(_at_)x =
'yes']">
<!-- do something -->
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
This example uses node-set function.. and tested with
Saxon 8.4.
Regards,
Mukul
--- Mat Bergman <matbergman(_at_)yahoo(_dot_)com> wrote:
My efforts to streamline my stylesheet into
something
well-formed are paying off with help from this list.
I
am currently working with XML input that looks like
this:
<menudata>
<menu name="link1">
<exsites>0</exsites>
</menu>
<menu name="link2">
<exsites>0</exsites>
<menu name="link2a">
<exsites>1</exsites>
<exsites>2</exsites>
</menu>
</menu>
</menudata>
The value of the <exsites> element determines if its
parent <menu> element will appear in the output,
based
on a $siteID parameter set in the stylesheet. In
some
cases, <menu> has multiple <exsites> children.
I'm not clear how to use XSL to say, "if the value
of
ANY <exsite> matches $siteID, then flag its parent's
node for different processing". Here's my attempt
(the
section where I'm in trouble is commented):
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:output method="xml" indent="yes"/>
<xsl:strip-space elements="*"/>
<!-- siteID determines if a link is displayed for a
specific cobrand -->
<xsl:param name="siteID" select="2"/>
<xsl:template match="/menudata">
<xsl:call-template name="write-menu">
<xsl:with-param name="items" select="menu"/>
</xsl:call-template>
</xsl:template>
<xsl:template name="write-menu">
<xsl:param name="items" select="/.."/>
<ul>
<xsl:for-each select="$items">
<xsl:call-template name="parseExclusions"/>
</xsl:for-each>
</ul>
</xsl:template>
<xsl:template name="parseExclusions">
<!-- Check <exsites> for a match against $siteID -
if
a match, don't display -->
<xsl:for-each select="exsites">
<xsl:if test="current()=$siteID">
<!-- This is where I need the stylesheet not to
write
the link if any of the <exsites> values match the
$siteID parameter -->
<!-- For now I'm just writing out the value if it
matches $siteID -->
<xsl:value-of select="current()"/>
</xsl:if>
</xsl:for-each>
<li>
<xsl:value-of select="@name"/>
<xsl:if test="menu">
<xsl:call-template name="write-menu">
<xsl:with-param name="items"
select="menu"/>
</xsl:call-template>
</xsl:if>
</li>
</xsl:template>
</xsl:stylesheet>
My instinct is to set a boolean variable if any
<exsite> element matches, then use that variable to
control the output. Something like this (in
pseudo-code):
<xsl:for-each select="exsites">
<xsl:if test="current()=$siteID">
<!-- set variable - var excludeFlag = 1 -->
</xsl:if>
</xsl:for-each>
<!-- write tag - if (excludeFlag!=1)? -->
<li>
<xsl:value-of select="@name"/>
?
</li>
<!-- /if -->
But of course an XSL variable is a different beast.
That seems to be my real weakness in XSL, grasping
the
concept of templates over variables.
Am I on the right track?
Thanks,
-Mat
____________________________________________________
Yahoo! Sports
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http://football.fantasysports.yahoo.com
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http://football.fantasysports.yahoo.com
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