Thanks for the quick answer.
My problem is not simply to convert elements to attributes. I also want to
change attributes names to have them as short as possible. e.g. param1 becomes
a, param2 becomes b, param3 becomes c ... to keep real attributes names, I use
the attribute called fields in the root element.
Here's an example :
<root fields="param1|param2|param3 ... ">
<e a="p1" b="p2" c="p3" d="p4" e="p5" f="p6" ... />
<e a=.... />
</root>
-----Message d'origine-----
De : James Fuller [mailto:jim(_dot_)fuller(_at_)ruminate(_dot_)co(_dot_)uk]
Envoyé : mardi 28 juin 2005 16:16
À : xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Objet : Re: [xsl] xsl transform
Philippe LAPLANCHE wrote:
Hello,
Does somebody has a neet way to convert this tree :
<?xml version="1.0" encoding="UTF-8"?>
<results>
<row>
<param1>p1</param1>
<param2>p2</param2>
<param3>p3</param3>
<param4>p4</param4>
<param5>p5</param5>
<param6>p6</param6>
...
<paramn>pn</paramn>
</row>
<row>
...
</row>
</results>
Into this one :
<?xml version="1.0" encoding="UTF-8"?>
<root fields="param1|param2|param3 ... ">
<e a="p1" b="p2" c="p3" d="p4" e="p5" f="p6" ... z="p26" aa="p27"
ab="p28" ... az="p52" ba="p53" .... zz="p702" />
</root>
something like http://www.dpawson.co.uk/xsl/sect2/N1553.html#d2005e139
will point u in the right direction.
gl, Jim Fuller
note : try to use a descriptive subject line helps those who have the
same prob later on
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