Aron:
Thank you very much for your solution and pointing me to the xsl:key
element.
Andreas
-----Original Message-----
From: Aron Bock [mailto:aronbock(_at_)hotmail(_dot_)com]
Sent: Sunday, June 26, 2005 8:46 PM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: RE: [xsl] Unique entries from substrings
Andreas,
You could approach it as a grouping problem, in which case this input:
<REPORT_ACCESS>
<REPORTS>
<REPORT>
<!-- not unique in list -->
<DATE>07/08/2005</DATE>
</REPORT>
<REPORT>
<!-- unique -->
<DATE>05/08/2005</DATE>
</REPORT>
<REPORT>
<!-- not unique in list -->
<DATE>07/08/2005</DATE>
</REPORT>
<REPORT>
<!-- unique 05-2005-->
<DATE>05/09/2005</DATE>
</REPORT>
<REPORT>
<!-- unique 07-2005-->
<DATE>07/09/2005</DATE>
</REPORT>
</REPORTS>
</REPORT_ACCESS>
with this xsl:
<?xml version="1.0" encoding="iso8859-1"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:output method="xml" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:key match="DATE" name="kDates" use="concat(substring(., 1, 2),
substring(., 7))"/>
<xsl:template match="DATE[generate-id(.) = generate-id(
key('kDates', concat(substring(., 1, 2), substring(.,
7)))[1])
]">
<xsl:value-of select="concat(substring(., 1, 2), substring(.,
7))"/>
<xsl:text>
</xsl:text>
</xsl:template>
<xsl:template match="DATE"/>
</xsl:stylesheet>
Yields:
<?xml version="1.0" encoding="UTF-8"?>
072005
052005
Of course, you may have to adjust to include the day, etc ... in which
case
you wouldn't need the substring and concat business.
--A
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