You're thinking procedurally. There's no "earlier" or "later" in XSLT -
order of execution is undefined.
Sounds as if you need a two phase stylesheet. Phase 1 computes a result tree
and puts this in a variable. Phase 2 considers whether a better result is
possible: if so, it applies a transformation to the first result (replacing
the relevant subtree with a better version and copying everything else
across unchanged); if not, it simply returns the result of the first phase.
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: Rahil [mailto:qamar_rahil(_at_)yahoo(_dot_)co(_dot_)uk]
Sent: 27 June 2005 11:23
To: XSL List
Subject: [xsl] replacing an output block
Hi
I want to replace a block of an HTML TABLE output in case
better results
are obtained later. So I have the result in 'first.html' of some
processing in 'first.xsl'.
first.html -- output
<HTML><BODY>
<TABLE>
<TR>
<TD>Want to replace this block with new output</TD>
<TD>Some other results from first.xsl</TD>
</TR>
</TABLE>
</BODY></HTML>
The block shown above has been copied as such in second.xsl using
<xsl:copy> and <xsl:copy-of>.
However as a result of processin some other block a better match is
obtained for the TR/TD[1] above and I would like to replace this new
finding with the old one. Given that I can easily locate the position
where this TR/TD[1] occurs, how do I overwrite the earlier output ?
Would appreciate any help or suggestions.
Thanks
Rahil
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