Anrew Welch wrote:
<xsl:template match="sub_a|sub_b|sub_c">
<xsl:variable name="copy"
select="boolean(*/following-sibling::*[local-name() =
preceding-sibling::*/local-name()])"/>
<xsl:if test="$copy">
<xsl:copy-of select="."/>
</xsl:if>
</xsl:template>
<xsl:if test="boolean(*/following-sibling::*[local-name() =
preceding-sibling::*/local-name()])"> works fine for my needs - thank
you very much! Could'nt have done it without you!
But it's probably O(n^3) in the number of siblings, so don't try it if
there's a large fanout.
Also the original post asked for all the elem_2's to be output: this code
surely omits the last one?
A 2.0 solution that's likely to be more efficient is
<xsl:for-each-group select="*" group-by="local-name()">
<xsl:if test="current-group()[2]">
<xsl:copy-of select="current-group()"/>
</xsl:if>
</xsl:for-each>
(However, this doesn't preserve the order of the children. The OP didn't say
whether that was a requirement.)
Michael Kay
http://www.saxonica.com/
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