I'm stuck again with my XSL. My XML Structure looks like:
<root>
<sub_a>
<elem_1/>
<elem_2/>
<elem_3/>
</sub_a>
<sub_b>
<elem_1/>
<elem_2/>
<elem_2/>
<elem_2/>
<elem_3/>
</sub_b>
<sub_c>
<elem_1/>
<elem_2/>
<elem_3/>
</sub_c>
</root>
The thing I want to do is display the element sub_b, because
it has subnodes which occur more than once (elem_2). I really
have no idea how to test for this - playing around for nearly
two hours now. Im using a loop like <xsl:for-each
select="/root/*"> and the output should look like
sub_b (this is the header)
elem_2
elem_2 (these are the 3 values of elem_2)
elem_2
How about:
<xsl:template match="sub_a|sub_b|sub_c">
<xsl:variable name="copy"
select="boolean(*/following-sibling::*[local-name() =
preceding-sibling::*/local-name()])"/>
<xsl:if test="$copy">
<xsl:copy-of select="."/>
</xsl:if>
</xsl:template>
cheers
andrew
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