This depends on the API of your processor, but I would expect you to be able
to construct a stylesheet parameter whose value represents a node-set, being
the set of document nodes that the stylesheet is to process. In the case of
a Microsoft processor, I'd expect this normally to be a DOM NodeList -
though I can't be certain without checking that a DOM NodeList allows nodes
from multiple documents.
So you should be able to create each of your A1..An documents as a DOM
Document, construct a NodeList containing the document nodes (or the
document elements if you prefer), and pass this to a stylesheet parameter
that you then treat as a node-set.
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: Ragulf Pickaxe [mailto:ragulf(_dot_)pickaxe(_at_)gmail(_dot_)com]
Sent: 16 June 2005 10:41
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] XSL transformations on hundreds of XML
documents held up against single large XML document
Hi all,
I have a problem that probably has to do with architechture (though I
do not know that).
My problem is this:
I have an XML "X" that I have gotten from a database.
With stylesheet "Y" I need to transform this data many times. Each
time differ by what is to be extracted from the "X" document. The
informations on what to be extracted are in other XML documents "A1,
A2, A3, etc." that are all generated in memory.
Usually I would be able to include the other documents in the XSL (as
a variable), but as they are generated in memory, I have no idea on
how to do this. The "X" document is also in memory at this time. It is
not viable to save them to disc at this time.
Is there some way of doing this, or is there something else
that I can do?
If the solution depends on development environment, I am using C# and
XSLT.NET (that is: XSL version 1.0).
In the time of writing this, I have come to think of another solution
which is the only thing I can think of at the moment, that is to add
the A1, etc. to X via DOM before transforming the whole with Y
stylesheet. If someone has anything to say about this solution, I
would be glad to hear it, as well.
X + A1 + Y -> B1
X + A2 + Y -> B2
X + A3 + Y -> B3
...
Thank you
Ragulf Pickaxe :-|
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