My process needs to take action on the first element in a list of
elements where the logic to determine first is the lowest
numeric value
of the sortorder attribute. I don't believe there is a
one-line way to
do this - I believe the entire list must be sorted, and then the
position of each element after sort compared to determine if
it is first.
Yes. Even in XSLT 2.0 this may be the best approach. 2.0 offers min/max
functions, but they give you the highest/lowest value, not the node having
that value.
Writing a recursive template/function might give you better performance than
sorting (linear rather than n*log(n)).
There is a one-line solution: $x[not($x/@sortorder < @sortorder)] but it's
quite likely to have poor (quadratic) performance.
You could consider using EXSLT math:highest() or math:lowest().
Or I'm sure there's something in Dimitre's box of tricks called FXSL.
Michael Kay
http://www.saxonica.com/
Is there a shorter/less expensive way to code the following
<xsl:for-each select="item">
<xsl:sort select="@sortorder" data-type="number" />
<xsl:if test="position() = 1">
<!-- this is the first element in the sorted list -->
</xsl:if>
</xsl:for-each>
I searched and found examples using this technique, but
nothing really
saying that this was the best or only approach.
Thanks in advance,
-John
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