From: John Robb <john_ok(_at_)tut(_dot_)by>
Reply-To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Can't save a node tree in a variable.
Date: Mon, 25 Jul 2005 17:12:04 +0300
Can you please help me?I want to save the sorted tree in a variable.
Whats wrong with the following xsl:
<xsl:variable name="sorted">
<xsl:apply-templates mode="copy" select="data/item"/>
</xsl:variable>
<xsl:template match="@*|node()">
<xsl:copy>
<xsl:apply-templates select="@*|node()" mode="copy">
<xsl:sort select="@sector"/>
<xsl:sort select="@subsector"/>
</xsl:apply-templates>
</xsl:copy>
</xsl:template>
And then I want to perform smth. like this:$sorted/item/@sector.
How is it possible to realize such a thing?
---
Didn't Michael explain this one earlier? You need to use a node-set
extension function unless you have the luxury of using XSLT 2.
For use in MSXML you will need to use ms:node-set($sorted) and declare
xmlns:ms="urn:schemas-microsoft-com:xslt"
in your stylesheet.
Joe
Joe
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