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RE: Can't save a node tree in a variable.

2005-07-25 07:23:56

From: John Robb <john_ok(_at_)tut(_dot_)by>
Reply-To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Can't save a node tree in a variable.
Date: Mon, 25 Jul 2005 17:12:04 +0300

Can you please help me?I want to save the sorted tree in a variable.
Whats wrong with the following xsl:
<xsl:variable name="sorted">
                <xsl:apply-templates mode="copy" select="data/item"/>
        </xsl:variable>
        <xsl:template match="@*|node()">
                <xsl:copy>
                        <xsl:apply-templates select="@*|node()" mode="copy">
                                <xsl:sort select="@sector"/>
                                <xsl:sort select="@subsector"/>
                        </xsl:apply-templates>
                </xsl:copy>
        </xsl:template>

And then I want to perform smth. like this:$sorted/item/@sector.
How is it possible to realize such a thing?
    ---

Didn't Michael explain this one earlier? You need to use a node-set extension function unless you have the luxury of using XSLT 2.
For use in MSXML you will need to use ms:node-set($sorted) and declare

xmlns:ms="urn:schemas-microsoft-com:xslt"

in your stylesheet.

Joe


Joe



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