You just generalize the solution I gave you. Instead of using "@lines" as a
specific attribute, you have to use count(*) or something similar to count
how many child elements there are.
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: John Robb [mailto:john_ok(_at_)tut(_dot_)by]
Sent: 25 July 2005 09:13
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] Can't solve the following XSL transformation
But how is it possible to determine,if the following Subsector can be
shown on this page or on the following.The problem is how to output
page-breaks exactly before sector/subsector only and no more than 25
elements per pag.
Mon, 25 Jul 2005 07:31:26 +0100, "Michael Kay" <mike(_at_)saxonica(_dot_)com>
писал(а):
Here's a simplified form of the problem. Given this input:
<chap>
<para lines="3"/>
<para lines="5"/>
<para lines="8"/>
etc
</chap>
produce a copy of the input, with a <page-break/> element inserted
after any
para that causes the cumulative number of lines to exceed 30.
The answer to this is what I call "sibling recursion", something
like this:
<xsl:template match="chap">
<xsl:copy>
<xsl:apply-templates select="para[1]"/>
</xsl:copy>
</xsl:template>
<xsl:template match="para">
<xsl:param name="lines-so-far" select="0"/> <!-- 0 is the default
value
of the parameter -->
<xsl:copy-of select="."/>
<xsl:choose>
<xsl:when test="$lines-so-far + @lines <= 30">
<xsl:apply-templates select="following-sibling::para[1]">
<xsl:with-param name="lines-so-far" select="$lines-so-far +
@lines"/>
</xsl:apply-templates>
</xsl:when>
<xsl:otherwise>
<page-break/>
<xsl:apply-templates select="following-sibling::para[1]"/>
</xsl:otherwise>
</xsl:choose>
</xsl:template>
Sibling recursion using xsl:apply-templates has a couple of
advantages over
call-template recursion: the sequence over which you are iterating
is an
implicit parameter (it's identified implicitly by the
context node);
and the
recursion terminates naturally when there are no more siblings.
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: John Robb [mailto:john_ok(_at_)tut(_dot_)by]
Sent: 25 July 2005 06:22
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] Can't solve the following XSL transformation
I'm a novice in XSLT and it's not very easy for me to realize the
second part of the algorithm.Can you please give me a
short example.
Thank you in advance.
Sun, 24 Jul 2005 23:26:09 +0100, "Michael Kay"
<mike(_at_)saxonica(_dot_)com>
писал(а):
The first stage is a classical grouping problem: see
http://www.jenitennison.com/xslt/grouping for advice on using
Muenchian
grouping in XSLT 1.0, or use the new xsl:for-each-group
instruction
in 2.0.
(Note, XSLT 1.1 doesn't really exist, it was a working
draft that
wasn't
followed up).
Insert the page breaks in a second pass through the
data. This is
a
little
tricky (I use it as an exercise on courses) and requires
processing
the
sequence using recursion, passing a parameter in the recursive
call
that
indicates the number of lines processed so far.
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: John Robb [mailto:john_ok(_at_)tut(_dot_)by]
Sent: 24 July 2005 22:45
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Can't solve the following XSL transformation
I'm a novice in XSLT and doesn't have any experience.Can
you help me
to perform the following transformation:
trasformed data should look as follows:
****************
Sector 1
****************
Subsector 1
++++++++++++++++
ID[t]Value
----------------
id1[t]value1
...
idN valueN
----------------
Subsector 2
++++++++++++++++
ID[t]Value
----------------
id1[t]value1
...
idN valueN
...
****************
Sector 2
****************
Subsector 1
++++++++++++++++
ID[t]Value
----------------
id1[t]value1
...
idN valueN
----------------
Subsector 2
++++++++++++++++
ID[t]Value
----------------
id1[t]value1
...
idN valueN
...
There is a limitation: no more than 25 data rows (idX
valueX) per
page.Page breaks (<span style="page-break-before:
always"></span>)
cannot be inserted in the middle of data section but before
sector/subsector only.I'm using XSLT v1.1.
Here is the xml:
<?xml version="1.0" encoding="iso-8859-1" ?>
<data>
[t]<item id="i1"[t]sector="s1"[t]subsector="u1">561</item>
[t]<item id="i10"[t]sector="s3"[t]subsector="u4">15</item>
[t]<item id="i22"[t]sector="s2"[t]subsector="u2">1234</item>
[t]<item id="i11"[t]sector="s1"[t]subsector="u2">123</item>
[t]<item id="i17"[t]sector="s1"[t]subsector="u3">165</item>
[t]<item id="i61"[t]sector="s2"[t]subsector="u1">346</item>
[t]<item id="i12"[t]sector="s2"[t]subsector="u5">3425</item>
[t]<item id="i2"[t]sector="s3"[t]subsector="u4">78</item>
[t]<item id="i14"[t]sector="s3"[t]subsector="u4">51</item>
[t]<item id="i21"[t]sector="s1"[t]subsector="u5">346</item>
[t]<item id="i39"[t]sector="s3"[t]subsector="u2">463</item>
[t]<item id="i44"[t]sector="s2"[t]subsector="u3">151</item>
[t]<item id="i89"[t]sector="s1"[t]subsector="u1">451</item>
[t]<item id="i81"[t]sector="s2"[t]subsector="u4">771</item>
[t]<item id="i36"[t]sector="s2"[t]subsector="u5">5654</item>
[t]<item id="i27"[t]sector="s3"[t]subsector="u3">362</item>
[t]<item id="i15"[t]sector="s1"[t]subsector="u5">234</item>
[t]<item id="i18"[t]sector="s3"[t]subsector="u2">73</item>
[t]<item id="i51"[t]sector="s3"[t]subsector="u5">567</item>
[t]<item id="i26"[t]sector="s1"[t]subsector="u4">17</item>
[t]<item id="i95"[t]sector="s3"[t]subsector="u5">67489</item>
[t]<item id="i13"[t]sector="s1"[t]subsector="u3">54</item>
[t]<item id="i71"[t]sector="s1"[t]subsector="u3">2</item>
[t]<item id="i23"[t]sector="s2"[t]subsector="u1">345</item>
[t]<item id="i7"[t]sector="s2"[t]subsector="u1">67</item>
[t]<item id="i80"[t]sector="s1"[t]subsector="u3">7754</item>
[t]<item id="i9"[t]sector="s3"[t]subsector="u4">343</item>
[t]<item id="i4"[t]sector="s1"[t]subsector="u2">51</item>
[t]<item id="i99"[t]sector="s3"[t]subsector="u5">5637</item>
[t][t]
[t][t]<sector id="s1">Sector 1</sector>
[t]<sector id="s2">Sector 2</sector>
[t]<sector id="s3">Sector 3</sector>
[t]<subsector id="u1">Subsector 1</subsector>
[t]<subsector id="u2">Subsector 2</subsector>
[t]<subsector id="u3">Subsector 3</subsector>
[t]<subsector id="u4">Subsector 4</subsector>
[t]<subsector id="u5">Subsector 5</subsector>
</data>
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