Thanks Mike for your help. I changed the stylesheet as
below. I have now introduced another parameter to the
named template called "element", which is the context
node during each recursive call.
But I don'nt know if my stylesheet will help the
original poster.
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
version="1.0">
<xsl:output method="xml" indent="yes" />
<xsl:template match="node() | @*" priority="5">
<xsl:copy>
<xsl:apply-templates select="node() | @*" />
</xsl:copy>
</xsl:template>
<xsl:template match="*" priority="6">
<xsl:copy>
<xsl:apply-templates select="@*" />
<xsl:attribute name="newSeq">
<xsl:call-template
name="concatenate-ancestor-attributes">
<xsl:with-param name="attr_value"
select="''" />
<xsl:with-param name="element" select="."
/>
<xsl:with-param name="ancestors"
select="ancestor::*" />
</xsl:call-template>
</xsl:attribute>
<xsl:apply-templates/>
</xsl:copy>
</xsl:template>
<xsl:template name="concatenate-ancestor-attributes">
<xsl:param name="attr_value" />
<xsl:param name="element" />
<xsl:param name="ancestors" />
<xsl:choose>
<xsl:when test="$element/parent::*">
<xsl:call-template
name="concatenate-ancestor-attributes">
<xsl:with-param name="attr_value"
select="concat($attr_value, $element/parent::*/@seq)"
/>
<xsl:with-param name="element"
select="$element/parent::*" />
<xsl:with-param name="ancestors"
select="$element/ancestor::*" />
</xsl:call-template>
</xsl:when>
<xsl:otherwise>
<xsl:value-of select="$attr_value" />
</xsl:otherwise>
</xsl:choose>
</xsl:template>
</xsl:stylesheet>
Regards,
Mukul
--- Michael Kay <mike(_at_)saxonica(_dot_)com> wrote:
Yes, this is a bug in your code.
Your recursive call of the named template doesn't
change the context node,
and therefore the expression "ancestor::*" will
select the same nodes each
time; and test="parent::*" will return true each
time if it returns true the
first time.
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: Mukul Gandhi [mailto:mukul_gandhi(_at_)yahoo(_dot_)com]
Sent: 08 July 2005 09:54
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] Concatenating the attribute
values of ancestors
I am actually getting error Exception in thread
"main"
java.lang.OutOfMemoryError with my stylesheet. It
seems recursing is not stopping.
I am using JRE 1.4.2_03. I am using Saxon 8.4.
Could
this be a bug?
Regards,
Mukul
--- Mukul Gandhi <mukul_gandhi(_at_)yahoo(_dot_)com> wrote:
Probably some sort of following logic is
required..
Please be beware, this is not tested.
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
version="1.0">
<xsl:output method="xml" indent="yes" />
<xsl:template match="node() | @*" priority="5">
<xsl:copy>
<xsl:apply-templates select="node() | @*" />
</xsl:copy>
</xsl:template>
<xsl:template match="*" priority="6">
<xsl:copy>
<xsl:apply-templates select="@*" />
<xsl:attribute name="newSeq">
<xsl:call-template
name="concatenate-ancestor-attributes">
<xsl:with-param name="attr_value"
select="''" />
<xsl:with-param name="anestors"
select="ancestor::*" />
</xsl:call-template>
</xsl:attribute>
<xsl:apply-templates/>
</xsl:copy>
</xsl:template>
<xsl:template
name="concatenate-ancestor-attributes">
<xsl:param name="attr_value" />
<xsl:param name="ancestors" />
<xsl:choose>
<xsl:when test="parent::*">
<xsl:call-template
name="concatenate-ancestor-attributes">
<xsl:with-param name="attr_value"
select="concat($attr_value, parent::*/@seq)" />
<xsl:with-param name="anestors"
select="ancestor::*" />
</xsl:call-template>
</xsl:when>
<xsl:otherwise>
<xsl:value-of select="$attr_value" />
</xsl:otherwise>
</xsl:choose>
</xsl:template>
</xsl:stylesheet>
Regards,
Mukul
--- Lakshmi narayana <lchintala(_at_)osi-tech(_dot_)com>
wrote:
Hi
I want a template which adds the attribute
values
of
its ancestors and
create an attribute to the current
node. The value to this attribute is the
result of
conactination of all the
node values added of its parents.
For example,
<A seq="1">
<B seq="2" />
<C seq="3">
<D seq="4" />
</C>
</A>
In the above xml, I want to concatenate all
the
seq
values of all ancestors
and its seq value also. And add new attribute
to the current node as newSeq with the result
concatenated value.
Note : if seq attribute is not there
concatenate
value "0".
Output should look like this.
<A seq="1" newSeq="1">
<B seq="2" newSeq="12"/>
<C seq="3" newSeq="13">
<D seq="4" newSeq="134"/>
</C>
<E newSeq="10">
<F seq="5" newSeq="105"/>
</E>
</A>
Thanks
Laxmi Narayana
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