Hi,
Please run below stylesheet and see:
<?xml version="1.0" encoding="UTF-8" ?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:output method="html" indent="yes" encoding="utf-8"/>
<xsl:template match="/">
<xsl:apply-templates select="a/b">
<xsl:with-param name="var" select="'chandu'"/>
</xsl:apply-templates>
</xsl:template>
<xsl:template match="b">
<xsl:param name="var"/>
<xsl:if test="$var = 'chandu'">
<xsl:message><xsl:value-of select="concat('hi ', $var)"/></xsl:message>
</xsl:if>
</xsl:template>
</xsl:stylesheet>
Cheers,
prakash
"ChandraShekar, A"
<ChandraShekar(_dot_)A(_at_)s To:
<xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com>
iemens.com> cc: (bcc:
omprakash.v/Polaris)
Subject: RE: [xsl] Converting
XML to XML
08/17/2005 07:29
PM
Please respond to
xsl-list
Is it possible to pass parameters to the xsl:template ? If yes, what is
the tag and example please ?
-----Original Message-----
From: David Carlisle [mailto:davidc(_at_)nag(_dot_)co(_dot_)uk]
Sent: Wednesday, August 17, 2005 5:50 PM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] Converting XML to XML
As explained in previous previous reply. remove the xsl:for-each.
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