Sorry, my mistake - you need to construct a new document that is
amenable to processing.
There are a number of ways of doing this, e.g. by creating a result-tree
- not strictly standard, I know but it illustrates the method:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
xmlns:ms="urn:schemas-microsoft-com:xslt">
....
<xsl:variable name="g">
<xsl:for-each select="*">
<group name="{local-name()}" />
</xsl:for-each>
</xsl:variable>
<xsl:apply-templates select="ms:node-set($g)/group">
<xsl:sort select="@name" />
</xsl:apply-templates>
<xsl:template match="group[(@name = preceding-sibling::group/@name)]"
priority="+1" />
<xsl:template match="group">
<group name="{(_at_)name}" />
</xsl:template>
.....
Alternatives:
1. use a multi-stage pipeline such as Apache Cocoon
2. nested translation in JSP
3. change the input format if you can
Michael Kay wrote:
These seem to be solutions to a different problem. The original XML has no
@name attributes.
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: Andrew Franz [mailto:afranz0(_at_)optushome(_dot_)com(_dot_)au]
Sent: 01 August 2005 22:11
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] Grouping problem
Mukul Gandhi wrote:
Thanks Mike for the XSLT 2.0 way to solve the problem. But it was
surprising for me that the problem cannot be solved in XSLT 1.0 using
preceding-sibling axis.
Regards,
Mukul
Solution #1:
<xsl:template match="groups">
<xsl:for-each select="group">
<xsl:sort select="@name" />
<xsl:if test="not(@name = preceding-sibling::group/@name)">
<group name="{(_at_)name}" />
</xsl:if>
</xsl:for-each>
</xsl:template>
Solution #2:
<xsl:template match="groups">
<xsl:for-each select="group">
<xsl:sort select="@name" />
<xsl:apply-templates select="." />
</xsl:for-each>
</xsl:template>
<xsl:template match="group[(@name = preceding-sibling::group/@name)]"
priority="+1" />
<xsl:template match="group">
<group name="{(_at_)name}" />
</xsl:template>
Solution #3:
<xsl:key name="k2" match="group" use="@name" />
<xsl:template match="groups">
<xsl:for-each select="group">
<xsl:sort select="@name" />
<xsl:apply-templates select="." />
</xsl:for-each>
</xsl:template>
<xsl:template match="group" priority="-1" />
<xsl:template match="group[generate-id() = generate-id(key('k2',
@name)[1])]">
group[<xsl:value-of select="@id" />]=<xsl:value-of select="@name"
/><br/>
</xsl:template>
On 8/1/05, Michael Kay <mike(_at_)saxonica(_dot_)com> wrote:
When comparing two node-sets,
X = Y
means "some $x in X equals some $y in Y"
But when you do
name(X) = name(Y)
you are comparing two strings, not two node-sets. If X is a
node-set, then
name(X) is the name of the first node in X, and name(Y) is
the name of the
first node in Y. (In XSLT 2.0, with version="2.0", you
would get an error
trying to apply name() to a node-set containing more than
one node. The
change has been made to catch this common mistake.)
In 2.0 you can write
select="*[not(name() = preceding-sibling::*/name())]"
but of course it would be more efficient to use xsl:for-each-group.
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: Mukul Gandhi [mailto:gandhi(_dot_)mukul(_at_)gmail(_dot_)com]
Sent: 01 August 2005 07:57
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Grouping problem
I have the following XML file -
<?xml version="1.0" encoding="UTF-8"?>
<root>
<a>1</a>
<b>2</b>
<d>3</d>
<d>4</d>
<b>5</b>
<b>6</b>
<c>7</c>
<c>8</c>
<a>9</a>
</root>
I am trying to do grouping operation with the following XSL -
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:output method="xml" version="1.0" encoding="UTF-8"
indent="yes"/>
<xsl:template match="/root">
<groups>
<xsl:for-each select="*[not(name() =
name(preceding-sibling::*))]">
<group name="{name()}" />
</xsl:for-each>
</groups>
</xsl:template>
</xsl:stylesheet>
I am expecting output -
<groups>
<group name="a" />
<group name="b" />
<group name="c" />
<group name="d" />
</groups>
But I get output -
<?xml version="1.0" encoding="UTF-8"?>
<groups>
<group name="a"/>
<group name="b"/>
<group name="d"/>
<group name="d"/>
<group name="b"/>
<group name="b"/>
<group name="c"/>
<group name="c"/>
</groups>
Where is the problem?
This is tested with Xalan-J 2.6.0 and Saxon 8.4
Regards,
Mukul
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