Hi,
Thanks again to everyone who has replied to these messages. I had no
idea how hard this would be. It seemed so simple when I explained it to
the client ;-)
I'm looking for an XPath expression that will find all elements whose
ancestors are the same. By "same" I mean their @name is the same at
each level of ancestry (and they appear in the same order).
For example, this expression would return a count of 2 for the
following XML when filtered on the "daughter" folder (or "mother" or
"grandfather" for that matter).
<root>
<folder name="grandfather">
<folder name="mother">
<folder name="daughter" />
</folder>
</folder>
<folder name="grandfather">
<folder name="mother">
<folder name="daughter" />
</folder>
</folder>
<folder name="grandmother">
<folder name="father">
<folder name="son" />
</folder>
</folder>
</root>
I know it's going to be something like this, but I just can't get my
head around it!
<xsl:copy-of select="/root//folder[(_at_)name = following-sibling::*/@name
and ancestor-or-self::*/@name =
following-sibling::*/@name/ancestor-or-self::*/@name" />
Thanks in advance!
Ted
--~------------------------------------------------------------------
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
To unsubscribe, go to: http://lists.mulberrytech.com/xsl-list/
or e-mail: <mailto:xsl-list-unsubscribe(_at_)lists(_dot_)mulberrytech(_dot_)com>
--~--