Try:
<xsl:template match="short/parameter">%s</xsl:template>
and
<xsl:template match="short">
<xsl:copy>
<xsl:apply-templates/>
</xsl:copy>
</xsl:template>
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: Meyer, Roland [mailto:roland(_dot_)meyer(_at_)siemens(_dot_)com]
Sent: 26 September 2005 08:45
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] RE: How to transform an embedded node into text
Hi,
I have to transform an XML file into another one and have the
following
problem. The source XML looks like this:
<root>
<short>Some text.
Description for the next node: <parameter id="8"
value="bldInvntryBladeIndex"/>
Some other text <parameter id="9" value="trapVbPrimaryBladeIndex"/>
And again some different text: <parameter id="10"
value="stm1CfgStm1Index"/>
</short>
</root>
The destination XML file should look like:
<root>
<short>Some text.
Description for the next node: %s
Some other text %s
And again some different text: %s
</short>
</root>
Is there a way to transform the "parameter" nodes in the embedded text
of node "short" into another text?
Best Regards,
Roland
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