I don't have the msxsl documentation to hand but I would guess that if your
parameter is named Date then you specify Date="2005-01-01".
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: stuart arnold [mailto:stuart(_dot_)arnold(_at_)comcast(_dot_)net]
Sent: 22 September 2005 23:59
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: RE: [xsl] % in xslt printing as ?
I treied that, I guess I'm missing something.
I'm calling at:
msxsl.exe testme.xml myfix.xsl param="2005-01-01" -o out.html
In the XSL, what should I have, I mean, how does it know that
that param
goes with what, eg
<xsl:param name="Date" />
Should I have more on the command line or the XSL?
Thanks for the reply and any help.
-----Original Message-----
From: Michael Kay [mailto:mike(_at_)saxonica(_dot_)com]
Sent: Thursday, September 22, 2005 6:38 PM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: RE: [xsl] % in xslt printing as ?
I'm trying to pass a variable to my xsl processor as well,
but I don't
know how to recive it in the XSL. What xsl command do I use?
Use <xsl:param name="nnnn"/> as a top-level element (a child of
xsl:stylesheet). Then refer to the parameter just like a variable, as
$nnnn. The way you actually supply the parameter a value
depends on the
processor API you are using.
Michael Kay
http://www.saxonica.com/
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