Hi,
Tempore 10:03:45, die 09/20/2005 AD, hinc in
xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com scripsit Shailesh Shinde
<shailesh(_at_)quagnito(_dot_)com>:
By using below tempalte I am get the output but with some other content
which i don't want. I have to display TopicGroup title in h1 and the rest of
the child element src values in h2 under that particular topicgroup.
Maybe you want the output to be:
<h1>Topic Group Title</h1>
<h2>Topic Title</h2>
<h2>Topic Title</h2>
<h2>Topic Title</h2>
<h1></h1>
In that case, try this stylesheet:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:output method="xml" indent="yes"/>
<xsl:template match="qxf">
<xsl:apply-templates select="docmain/Chapter/TopicGroup"/>
</xsl:template>
<xsl:template match="TopicGroup">
<h1><xsl:value-of select=".//src"/></h1>
<xsl:apply-templates select="Topic"/>
</xsl:template>
<xsl:template match="Topic">
<h2><xsl:value-of select="Title//src"/></h2>
</xsl:template>
</xsl:stylesheet>
regards,
--
Joris Gillis (http://users.telenet.be/root-jg/me.html)
Don't send spam. I don't like it and it is illegal.
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