Sorry, Think I jumped the gun there,
The line above did not quite do what I expected. With the same 3 xml
documents above I used:
<?xml version='1.0'?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<!-- Pseudo xsl -->
<xsl:template match="/">
<html>
<body>
<xsl:if test="not(/Root/foo/@att!='hi')">
<xsl:apply-templates/>
</xsl:if>
</body>
</html>
</xsl:template>
</xsl:stylesheet>
The third document outputted information when it should not have.. Any
other thoughts, did I mess something up?
Spencer
On 9/15/05, Spencer Tickner <spencertickner(_at_)gmail(_dot_)com> wrote:
Perfect, Thanks a lot Joris
On 9/15/05, Joris Gillis <roac(_at_)pandora(_dot_)be> wrote:
Tempore 20:28:26, die 09/15/2005 AD, hinc in
xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com scripsit Spencer Tickner
<spencertickner(_at_)gmail(_dot_)com>:
This should be a relatively simple solution but my mind ain't quite
working right today and google isn't being good to me.
I'm looking to test if any elements of a certain type do NOT have an
attribute with a specific value in an entire xml doc. For instance.
<!-- Pseudo xsl -->
<xsl:template match="/">
<xsl:if test="<!-- if all the foo elements in the doc only contain the
attribute att with a value of hi, don't output -->">
<xsl:apply-templates/>
</xsl:if>
</xsl:template>
"not(/Root/foo/@att!='hi')"
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