Hi,
Tempore 10:39:52, die 09/08/2004 AD, hinc in
xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com scripsit Shailesh
<shailesh(_at_)quagnito(_dot_)net>:
Using xslt 1.0 I have to extract the value of <test2> which is in <test1
id="0000001"> of update.xml and put it in <test2> which is in <test1
id="0000001"> of source.xml.
This should updates the <test2> of source.xml without any other changes.
Try applying the following stylesheet to 'source.xml'.
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output method="xml" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:output method="xml" />
<xsl:variable name="update" select="document('update.xml')"/>
<xsl:key name="id" match="*" use="@id"/>
<xsl:template match="*[(_at_)id]">
<xsl:variable name="id" select="@id"/>
<xsl:copy>
<xsl:apply-templates select="@*" />
<xsl:for-each select="$update">
<xsl:copy-of select="key('id',$id)/*"/>
</xsl:for-each>
</xsl:copy>
</xsl:template>
<xsl:template match="node()|@*">
<xsl:copy>
<xsl:apply-templates select="node()|@*" />
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
--
Joris Gillis (http://users.telenet.be/root-jg/me.html)
Deserta faciunt et innovationem appelant
--~------------------------------------------------------------------
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
To unsubscribe, go to: http://lists.mulberrytech.com/xsl-list/
or e-mail: <mailto:xsl-list-unsubscribe(_at_)lists(_dot_)mulberrytech(_dot_)com>
--~--