On 9/6/05, Manfred Staudinger <manfred(_dot_)staudinger(_at_)gmail(_dot_)com>
wrote:
Hi all,
Given a rather long list of unique names I want to know for a
certain name if it is on that list. The stylesheet below does
this, but is this the best (most efficient) solution? In the most
common case around 95% of the names will be found.
- is the key element correct (I have no use for @use)?
- should I sort the names?
In the real stylesheet the names represent files and are used
to avoid a file-not-found for doc(). They are retrieved by means
of collection().
<?xml version="1.0" encoding="UTF-8" ?>
<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:key name="find" match="*" use="."/>
<xsl:template match="/">
<xsl:variable name="Index-alt">
<doc>
<name>
<xsl:text>schmid_hans</xsl:text>
</name>
<name>
<xsl:text>prunauer_katharina</xsl:text>
</name>
<name>
<xsl:text>senkenwald_wolfgang</xsl:text>
</name>
</doc>
</xsl:variable>
<xsl:value-of select="empty(key('find', 'prunauer_regina', $Index-alt))"/>
<xsl:value-of select="empty(key('find', 'strada_jacopo', $Index-alt))"/>
</xsl:template>
</xsl:stylesheet>
Not sure about your key definition:
* matches all elements
. gets all the descedant text nodes and concatenates them together
so
<name>schmid_hans</name>
and
<doc><name>schmid_</name><name>hans</name></doc>
when keyed with 'schmid_hans' would both return an element, but is
probably not want you want.
If might be better to match on text() than on *
cheers
andrew
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