Hi Wendel,
Thanks for the help. I think I have things working now.
Matt
-----Original Message-----
From: Wendell Piez [mailto:wapiez(_at_)mulberrytech(_dot_)com]
Sent: Thursday, September 01, 2005 5:39 PM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] Copying-Replacing Elements
Matt,
Your are on the right track. What you need is a "modified identity
transformation", an idiom widely used in XSLT to deal with problems like
yours.
At 05:43 PM 9/1/2005, you wrote:
The original node would look something like this...
<data>
<cell id="8" flag="false">
<name>bob</name>
<member>5</member>
</cell>
</data>
The output would like something like this...
<data>
<cell id="8" flag="true">
<name>matt</name>
</cell>
</data>
<data>
<cell id="8" flag="false">
<name>bob</name>
<member>5</member>
</cell>
</data>
I'm thinking the xsl would look something like this
<xsl:template name="createNewSiblingMember" match="something that
returns a single node">
<xsl:copy-of select=".">
...do some kind of transformations...
</xsl:copy-of>
<xsl:copy-of select="."/>
</xsl:template>
<xsl:template match="data">
<xsl:copy>
<!-- the copy instruction copies the element, but not its
attributes or children -->
...what do you want to do? add new stuff?
change values of attributes or child elements?
based on what rules?...
</xsl:copy>
<!-- the copy-of instruction "deep-copies" the node as is -->
<xsl:copy-of select="."/>
</xsl:template
Check out more in the FAQ at
http://www.dpawson.co.uk/xsl/sect2/identity.html
Cheers,
Wendell
======================================================================
Wendell Piez
mailto:wapiez(_at_)mulberrytech(_dot_)com
Mulberry Technologies, Inc. http://www.mulberrytech.com
17 West Jefferson Street Direct Phone: 301/315-9635
Suite 207 Phone: 301/315-9631
Rockville, MD 20850 Fax: 301/315-8285
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