On 9/3/05, Joe Fawcett <joefawcett(_at_)hotmail(_dot_)com> wrote:
Can anyone explain why the first item being passed to the template has any
preceding-sibling?
XML:
<root>
<item id="1" />
<item id="2" />
<item id="3" />
<item id="4" />
<item id="5" />
<item id="6" />
<item id="7" />
<item id="8" />
<item id="9" />
<item id="10" />
</root>
XSLT:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:param name="groupSize" select="3" />
<xsl:template match="/">
<new>
<xsl:call-template name="groupItems">
<xsl:with-param name="items" select="root/item" />
</xsl:call-template>
</new>
</xsl:template>
<xsl:template name="groupItems">
<xsl:param name="items" />
<xsl:variable name="itemCount" select="count($items)" />
<xsl:if test="$itemCount > 0">
<group>
<xsl:for-each select="$items">
<xsl:if test="position() <= $groupSize">
<newItem id="{(_at_)id}">
<xsl:if test="position() = 1">
<xsl:attribute name="preceding-sibling-count">
<xsl:value-of select="count(preceding-sibling::item)" />
</xsl:attribute>
</xsl:if>
</newItem>
</xsl:if>
</xsl:for-each>
</group>
<xsl:call-template name="groupItems">
<xsl:with-param name="items" select="$items[position() > $groupSize]"
/>
</xsl:call-template>
</xsl:if>
</xsl:template>
</xsl:stylesheet>
Result (msxml version 4):
<new>
<group itemCount="10">
<newItem id="1" preceding-sibling-count="0"/>
<newItem id="2"/>
<newItem id="3"/>
</group>
<group itemCount="7">
<newItem id="4" preceding-sibling-count="3"/>
<newItem id="5"/>
<newItem id="6"/>
</group>
<group itemCount="4">
<newItem id="7" preceding-sibling-count="6"/>
<newItem id="8"/>
<newItem id="9"/>
</group>
<group itemCount="1">
<newItem id="10" preceding-sibling-count="9"/>
</group>
</new>
Why doesn't the preceding-sibling-count show zero, or am I just up too late?
Because this is exactly the number of preceding siblings of the current node.
The "preceding-sibling" axis' scope is the current document, not a
dynamically defined node-list.
Most probably you want something else -- not the count of preceding siblings?
Cheers,
Dimitre Novatchev
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