I need the text but your suggested expression <xsl:value-of
select="b/c[(_at_)type='pdf'][1]"/> gives the same output.
-----Original Message-----
From: cknell(_at_)onebox(_dot_)com [mailto:cknell(_at_)onebox(_dot_)com]
Sent: Friday, 2 September 2005 11:20 AM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: RE: [xsl] Extract First node
Do you want the element or the text contained in the element? The xsl:value-of
returns the latter. If that is what you want then change your template to this:
<xsl:value-of select="b/c[(_at_)type='pdf'][1]"/>
If it is the former then your template should be:
<xsl:copy-of select="b/c[attribute::className='pdf'][1]"/>
--
Charles Knell
cknell(_at_)onebox(_dot_)com - email
-----Original Message-----
From: SINGH Navpreet <Navpreet(_dot_)SINGH(_at_)Tenix(_dot_)com>
Sent: Fri, 2 Sep 2005 10:23:12 +1000
To: <xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com>
Subject: [xsl] Extract First node
Hi
I am having a problem with XPath expression for XSLT. I am trying to extract a
node from xml with a special attribute. For example
<a>
<b>
<c type="html">HTML file</c>
</b>
<b>
<c type="text">Text File</c>
</b>
<b>
<c type="pdf">First Pdf File</c>
</b>
<b>
<c type="pdf">Second Pdf File</c>
</b>
<b>
<c type="rtf">Rtf File</c>
</b>
</a>
Element <c> can appear in any order and there could be a number of <c> with
attribute type="pdf". I want to extract the first occurence of the element <c>
which has a attribute type="pdf". I tried to extract it with
<xsl:value-of select="b/c[attribute::className='pdf'][1]"/>
after matching the template for <a>. But I am getting "First Pdf File Second
Pdf File". Can anyone tell me where I am making mistake. I am using Saxon-B8.5.
Thanks
Navpreet.
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