could do that lots of different ways
how about
<xsl:template match="overview[info]">
<info><xsl:apply-templates select="info"/></info>
</xsl:template>
do whatever you want with info in an info template
your previous template should probably have been something like
<xsl:template
match="overview/info[following-sibling::*[1][local-name()='info']">
<info><xsl:value-of select="."/><xsl:text> </xsl:text><xsl:vaue-of
select="following-sibling::*[local-name()='info']"/></nfo>
</xsl:template>
and then
<xsl:template match="overview/info"/>
to get other infos out of the picture
I am however 99% certain that this is not the way you should do it ,
and instead use the other method (there is always a possiblity I don't
know some requirement you have that makes this reasonable) given this
slight hint of uncertainty I have used a rather bad xpath to get what
should have been a lot easier to get, see former example.
On 10/18/05, Annmarie Rubin (anrubin) <anrubin(_at_)cisco(_dot_)com> wrote:
Thanks for the tip, Michael.
I want to generate a single element to replace two consecutive info
elements that are children of an overview element and have the same name
(and concatenate their contents.) There will be no more than one pair
of these info elements in each overview element. I don't want to
generate a single element containing all duplicate elements.
For example, this code finds the info element that is a child of an
overview element and whose next following sibling is also an info
element.
<xsl:template match="overview/info[following-sibling::*[1][self::info]]"
At this point, I'm stuck. How do I concatenate both elements?
thanks,
Ann Marie
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