Namespace on output node but not not in source

Hi:

I have a xsl with a namespace declared

<xsl:transform xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
        version="1.0"
        xmlns:xs="http://www.w3.org/2001/XMLSchema";>

so i can make some lookups on a xsd file

 <xsl:variable name="tipo"
select="$schema/xs:schema/xs:element[(_at_)name=$nome]/@type"/>

and that's all i do, i don't copy any node from $schema to the output tree.

However, this

        <xsl:template match="/">
                <table>
                        <xsl:apply-templates
select="(//Menu)[position()=$pos]"/>
                </table>
        </xsl:template>

produces a

<table xmlns:xs="http://www.w3.org/2001/XMLSchema";>
     <...>
</table>

and i don't understand why, and i don't want it there.

I add a exclude-result-prefixes="xs" but it seems it makes no diference.

Why is this?


Thanks.

--~------------------------------------------------------------------
XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
To unsubscribe, go to: http://lists.mulberrytech.com/xsl-list/
or e-mail: <mailto:xsl-list-unsubscribe(_at_)lists(_dot_)mulberrytech(_dot_)com>
--~--