First, you put the result in a variable:
<xsl:variable name="x">
<xsl:for-each select=...
<something/>
</xsl:for-each>
</xsl:variable>
In XSLT 1.0, to address into this variable, you need the xx:node-set()
extension (in your case, xalan:nodeset()).
In 2.0, you can use it directly.
<xsl:variable name="evens" as="xs:integer*">
<xsl:for-each select="1 to 100">
<xsl:sequence select=". * 2"/>
</xsl:for-each>
</xsl:variable>
<xsl:value-of select="$evens[5]"/>
Though for this example it's easier to use an XPath "for" expression.
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: Ferdinand Soethe [mailto:xsl-list(_at_)soethe(_dot_)net]
Sent: 14 October 2005 18:18
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] (How) can I randomly access the result of a
<xsl:for-each select="...?
Perhaps I have searched for the wrong key words ...
Is it possible to randomly access each member of the set of nodes
created by <xsl:for-each select="... I know I can find the position of
the currently processed node with position() and use the first() and
last() to access the respective nodes. But can I also access each
individual member with something like xyz[memberNo]?
I figure that there should be a 'root' element that contains the set
but I haven't found a way to address that.
Btw: I'm using xalan-J
Thanks a lot.
--
Ferdinand Soethe
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