I'm still trying solutions for this problem.
my source xml:
<String>YA Cahier de brouillon Tual S. Jean</String>
I tried this xsl:
<xsl:variable name="strMatches" as="xs:string*"
select="('YA', 'Tual', 'S. Jean')"/>
<xsl:template match="String">
<xsl:element name="{name(.)}">
<xsl:value-of select="for $i in (1 to
count($strMatches)) return
replace(text(),$strMatches[$i],'test')"/>
</xsl:element>
</xsl:template>
but it only gives me:
<String>test Cahier de brouillon Tual S. Jean YA
Cahier de brouillon test S. Jean YA Cahier de
brouillon Tual test</String>
as you can see i can only get to change each string in
$strMatches per iteration but i want to output only
one single string.
desired output is:
<String>test Cahier de brouillon test test</String>
am i close to solving this problem or am i way far
out???
-- UlyLee
--- UlyLee <ulyleeka(_at_)yahoo(_dot_)com> wrote:
I actually had an idea on how to go around with this
but i dont how to properly code it in XSLT.
<String>Name1 and Name3 also Name4 Name5 but not
Name2</String>
<table>
<tr>
<td>Name1</td>
<td>ValidName1</td>
</tr>
<tr>
<td>Name3</td>
<td>ValidName3</td>
</tr>
<tr>
<td>Name4 Name5</td>
<td>ValidName4 ValidName5</td>
</tr>
</table>
* i'll assign first into a variable, validStr, all
the
td[1] in table
* test if contents of String is equal to $validStr
* if true then i'll assign to a variable, match, the
sibling of the td[1] that matches $validStr[1]
* then call replace(String, $validStr[1], $match)
* then run this all over again but this time passing
the replaced string as new string to process and
remove the $validStr[1] in $validStr to avoid
repetition.
output should be:
<String><ValidName>ValidName1</ValidName> and
<ValidName>ValidName3</ValidName> also
<ValidName>ValidName4 ValidName5</ValidName> but not
Name2</String>
i hope that makes sense :D
-- UlyLee
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