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Re: XSL formatting

2005-12-23 02:44:55
Hi,

Adding an additional for-each that will iterate on the img elements from the redundant element that do not have a corresponding img in missing should do it:

<xsl:transform version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
  <xsl:template match="/imgBook">
    <html>
      <head>
        <title>Sample</title>
      </head>
      <body>
        <table border="1">
          <tr>
            <td>missing</td>
            <td>redundant</td>
          </tr>
          <xsl:for-each select="missing/img">
            <xsl:variable name="pos" select="position()"/>
            <tr>
              <td>
                <xsl:value-of select="@name"/>
              </td>
              <td>
                <xsl:value-of select="../../redundant/img[$pos]/@name"/>
              </td>
            </tr>
          </xsl:for-each>
          <xsl:variable name="mc" select="count(missing/img)"/>
          <xsl:for-each select="redundant/img[position()>$mc]">
            <tr>
              <td/>
              <td>
                <xsl:value-of select="@name"/>
              </td>
            </tr>
          </xsl:for-each>
        </table>
      </body>
    </html>
  </xsl:template>
</xsl:transform>

---------------------------------------------------------------------
George Cristian Bina
<oXygen/> XML Editor, Schema Editor and XSLT Editor/Debugger
http://www.oxygenxml.com


Shailesh Shinde wrote:
Hi,

Same number of images are not there in both missing and redundant.

Thanks,
Shailesh


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