A useful technique...
1. In your CSS file, define odd & even rows as follows:
.row0 { color: #FFFFFF; }
.row1 { color: #FFD0FF; }
2. In your XSL stylesheet:
<xsl:for-each select="item">
<tr class="row{(position() mod 2)}">...</tr>
</xsl:for-each>
Michael Kay wrote:
The usual way to handle such requirements is with code such as this:
<xsl:for-each select="item">
<xsl:choose>
<xsl:when test="position() mod 2 = 0">...</xsl:when>
<xsl:otherwise>...</xsl:otherwise>
</xsl:choose>
</xsl:for-each>
Withing the for-each, the total number of items is available as the result
of the function last().
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: Dietmar Klotz [mailto:dklotz(_at_)cellular(_dot_)de]
Sent: 09 December 2005 20:12
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] counting in for each
I am making a list with "for each" and if the list is 1 or 3
items it should
change the state of display. And I would also like to change the Icon
depending on how many objects there are....so object 1 has
icon 1...object 2
icon 2
So my question. Is it possible to count how many Items there
are in a node?
And do I know where I am in a for each?
Thanks to all!
Dietmar Klotz
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