This has nothing to do with data types: it's a context problem. The meaning
of a relative path expression like "@id" depends on the context node. In
your match pattern, @id is an attribute of a data-store element; in the
select expression, it is an attribute of a data-sink element.
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: cknell(_at_)onebox(_dot_)com [mailto:cknell(_at_)onebox(_dot_)com]
Sent: 13 December 2005 15:59
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] xsl data type problem? two values appear to be
equal but ...
Here is the opening part of the problem template:
--------------
<xsl:template match="data-store[(_at_)id=$node-id]">
<node type="{local-name(.)}" id="{(_at_)id}" name="{name}">
--------------
This selects the node I expect. So far, so good.
Now, further along in the template I pass a parameter to a
called template:
<xsl:with-param name="ds-predecessor"
select="/fssc/component-list/processes/process[data-sinks/data
-sink[.=$node-id]]" />
This works, too, but if I define the parameter in this way,
no nodes are passed:
<xsl:with-param name="ds-predecessor"
select="/fssc/component-list/processes/process[data-sinks/data
-sink[(_dot_)=(_at_)id]]" />
The 'match' treats these two values as the same, but the
'select' seems to treat them differently.I have output both
values using 'xsl:value-of' and they seem the same.
I also used the compare() function on the two and got a
return value of '0'.My hypothesis is that they must be of
different data types and that's why the called template
behaves differently when called with one or the other.
I have been searching the index of XPath 2.0 Programmer's
Reference looking for a function that will return the data
type of a node or variable passed to it, but I must have the
wrong idea of what I'm looking for, because I can't find one.
Will someone kindly tell me why these two are the same and
different? Thanks.
--
Charles Knell
cknell(_at_)onebox(_dot_)com - email
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