Hi,
Please check this xsl.
<?xml version='1.0' encoding='UTF-8'?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
xmlns:fo="http://www.w3.org/1999/XSL/Transform";>
<xsl:output method="xml"/>
<xsl:key name="rec" match="row" use="question_id"/>
<xsl:template match="/recordset">
<xsl:for-each select="row">
<xsl:if test="generate-id(.) = generate-id(key('rec', question_id))">
<xsl:text>
</xsl:text>
Answers for question <xsl:value-of select="question_id"/>
</xsl:if>
<xsl:text>
</xsl:text>
<xsl:value-of select="key('rec', question_id)/answer"/>
<xsl:text>
</xsl:text>
</xsl:for-each>
</xsl:template>
regards,
prakash
Phillip B Oldham
<phillip.oldham@ To: XSL
<xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com>
kilo75.com> cc: (bcc:
omprakash.v/Polaris)
Subject: [xsl] Grouping
12/07/2005 02:13
PM
Please respond
to xsl-list
Hi all
I've the following xml doc:
<recordset>
<row>
<question_id>1</question_id>
<answer>blah blah blah...</answer>
</row>
<row>
<question_id>1</question_id>
<answer>blah blah blah...</answer>
</row>
<row>
<question_id>2</question_id>
<answer>blah blah blah...</answer>
</row>
<row>
<question_id>2</question_id>
<answer>blah blah blah...</answer>
</row>
...etc...
</recordset>
I'd like to be able to group the output so I get the following:
Answers to question 1:
- blah blah blah...
- blah blah blah...
Answers to question 2:
- blah blah blah...
- blah blah blah...
...etc...
There isn't a fixed number of answers to each question, so grouping on a
set of say 10 isn't possible. I've tried using preceeding-sibling, but
can't seem to get anywhere with it.
Any ideas?
Phill
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