Hi, thank you for your answer, but i think i explain my problem in a bad
way.
I say exactly r11/c1, i want to use in my next math operations the value
that i'll found in that child (r11/c1) of xsl file.
I hope i explain my problem in a right way.
Excuse me for my poor english ;)
Thank you
A.V.
-----Messaggio originale-----
Da: G. Ken Holman [mailto:gkholman(_at_)CraneSoftwrights(_dot_)com]
Inviato: lunedì 5 dicembre 2005 0.00
A: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Oggetto: Re: [xsl] IQuestion about XSLT and Math Operations
At 2005-12-04 13:48 +0100, Villani Alessandro wrote:
<c2>
How I can perform, if possible , this type of
operation: [value of r11/c1 + value of r12/c1] whithout use xsl:param.
</c2>
You have probably missed that the division operator in XPath is "div"
since "r11/c1" means "children c1 of children r11".
Use <xsl:value-of select="r11 div c1 + r12 div c1"/>
I hope this helps.
. . . . . . . . . . . Ken
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