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RE: position

2005-12-01 01:08:56
position() gives the position of a node in the current node list, which in
this case is the set of nodes selected by the apply-templates call, which is
a list of length one, because you only selected the last one.

xsl:number would probably suit your purpose better.

You're not trying to count the number of tags, of course, but the number of
elements. Most elements have two tags, a start tag and an end tag.

Michael Kay
http://www.saxonica.com/ 

-----Original Message-----
From: Chandrasekhar A [mailto:chandrashekarrvt(_at_)gmail(_dot_)com] 
Sent: 01 December 2005 06:47
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] position

Hello,

     I am trying to find number of tags in my xml using XSLT. 
The XSLT is

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
xmlns:fo="http://www.w3.org/1999/XSL/Format";>
<xsl:output method="text"/>
      <xsl:template match="/">                
                      <xsl:apply-templates 
select="dataroot/ReferenceTaskDb[last()]"/>
      </xsl:template>
      <xsl:template match="ReferenceTaskDb">
              <result> <xsl:value-of select="position()"/></result>
      </xsl:template>
</xsl:stylesheet>

   It is returning 1. What is the wrong here ?

Thanks and Regards,
Chandu

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