Thanks, I couldn't find that. On closer examination, it seems the standard set
of XPath2 functions does not include a square root function. I don't feel up to
writing my own, so I won't procede with the standard deviation function.
--
Charles Knell
cknell(_at_)onebox(_dot_)com - email
-----Original Message-----
From: Xia Li <xli(_at_)galdosinc(_dot_)com>
Sent: Wed, 25 Jan 2006 13:46:02 -0800
To: <xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com>
Subject: RE: [xsl] Creating XPath2 functions:passing a set of nodes, what is
the signature construction?
You may use occurrence indicator "*" or "+" in <xsl:param>, such as
<xsl:param ... as="xs:double*">
to indicate that a sequence of double is expected.
Lisa
-----Original Message-----
From: cknell(_at_)onebox(_dot_)com [mailto:cknell(_at_)onebox(_dot_)com]
Sent: Wednesday, January 25, 2006 1:26 PM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Creating XPath2 functions:passing a set of nodes, what is
the signature construction?
I am learning XPath2 using Saxon 8.6. I'd like to create a funtion to
compute the standard deviation of the value of a set of nodes. Is there
some special way to construct the signature of the function when the
argument is a set of nodes as opposed to a single node?
I have written a funtion that takes a single node as an argument of type
xs:double. Is there some special way to state that the function will
take a set of nodes of type xs:double, or do I simply state that the
argument will be of type xs:double?
--
Charles Knell
cknell(_at_)onebox(_dot_)com - email
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