The first way would also work in XSLT1, the second way uses xpath2
regexp to sort media1 as media01.
It only works if all the numeric parts are one or two digits.
I can't think of an easy way of generalizing it, however.
Michael Kay
http://www.saxonica.com/
David
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
version="2.0">
<xsl:output indent="yes" omit-xml-declaration="yes"/>
<xsl:template match="x">
<x>
<a>
<xsl:for-each select="server">
<xsl:sort
select="translate(substring-before(@dn, '.'),'0123456789','')"
data-type="text"
order="ascending"/>
<xsl:sort
select="translate(substring-before(@dn,
'.'),'abcdefghijklmnopqrstuvwxyz','')"
data-type="number"
order="ascending"/>
<xsl:copy-of select="."/>
</xsl:for-each>
</a>
<b>
<xsl:for-each select="server">
<xsl:sort
select="replace(@dn,'([^0-9])([0-9])([^0-9])','$10$2$3')"/>
<xsl:copy-of select="."/>
</xsl:for-each>
</b>
</x>
</xsl:template>
</xsl:stylesheet>
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