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Re: Re: Collecting sibling nodes under groupings

2006-01-13 04:25:31
Hi David.
With the exception of the terminated <xsl:for-each select="current-group()"/>, it worked right out of the box.
Thanks to you and Michael for your help,
Mark

----- Original Message ----- From: "David Carlisle" <davidc(_at_)nag(_dot_)co(_dot_)uk>
To: <xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com>
Sent: Friday, January 13, 2006 4:50 AM
Subject: Re: [xsl] Re: Collecting sibling nodes under groupings


<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
version="2.0">
<xsl:template match="/">
<SubjectList>
<xsl:for-each-group select="/List/Entry" group-by="Subject">
<SubjectEntry>
<xsl:value-of select="Subject"/>
<xsl:for-each select="current-group()"/>
<Book>
<xsl:copy-of select="*[not(self::Subject)]"/>
</Book>
</xsl:for-each>
</SubjectEntry>
</xsl:for-each-group>
</SubjectList>
</xsl:template>
</xsl:stylesheet>

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