Use an attribute value template, id="{Location}"
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: dan(_at_)streampad(_dot_)com [mailto:dan(_at_)streampad(_dot_)com]
Sent: 08 January 2006 08:05
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] xml not well-formed
In the below example, I would like to make the div id = <xsl:value-of
select="Location"/>, but this will not work since it is not
well-formed
xml. Is there any way to reference this node without using an
xml element?
Thanks,
Dan
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:template match="/">
<html>
<body>
<xsl:for-each select="songlist/song">
<div id="<xsl:value-of select="Location"/>"><xsl:value-of
select="Name"/></div>
</xsl:for-each>
</body>
</html>
</xsl:template>
</xsl:stylesheet>
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